Optimal. Leaf size=173 \[ \frac{2 (a+b x) \sqrt{d+e x} (A b-a B)}{b^2 \sqrt{a^2+2 a b x+b^2 x^2}}-\frac{2 (a+b x) (A b-a B) \sqrt{b d-a e} \tanh ^{-1}\left (\frac{\sqrt{b} \sqrt{d+e x}}{\sqrt{b d-a e}}\right )}{b^{5/2} \sqrt{a^2+2 a b x+b^2 x^2}}+\frac{2 B (a+b x) (d+e x)^{3/2}}{3 b e \sqrt{a^2+2 a b x+b^2 x^2}} \]
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Rubi [A] time = 0.102103, antiderivative size = 173, normalized size of antiderivative = 1., number of steps used = 5, number of rules used = 5, integrand size = 35, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.143, Rules used = {770, 80, 50, 63, 208} \[ \frac{2 (a+b x) \sqrt{d+e x} (A b-a B)}{b^2 \sqrt{a^2+2 a b x+b^2 x^2}}-\frac{2 (a+b x) (A b-a B) \sqrt{b d-a e} \tanh ^{-1}\left (\frac{\sqrt{b} \sqrt{d+e x}}{\sqrt{b d-a e}}\right )}{b^{5/2} \sqrt{a^2+2 a b x+b^2 x^2}}+\frac{2 B (a+b x) (d+e x)^{3/2}}{3 b e \sqrt{a^2+2 a b x+b^2 x^2}} \]
Antiderivative was successfully verified.
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Rule 770
Rule 80
Rule 50
Rule 63
Rule 208
Rubi steps
\begin{align*} \int \frac{(A+B x) \sqrt{d+e x}}{\sqrt{a^2+2 a b x+b^2 x^2}} \, dx &=\frac{\left (a b+b^2 x\right ) \int \frac{(A+B x) \sqrt{d+e x}}{a b+b^2 x} \, dx}{\sqrt{a^2+2 a b x+b^2 x^2}}\\ &=\frac{2 B (a+b x) (d+e x)^{3/2}}{3 b e \sqrt{a^2+2 a b x+b^2 x^2}}+\frac{\left (2 \left (\frac{3}{2} A b^2 e-\frac{3}{2} a b B e\right ) \left (a b+b^2 x\right )\right ) \int \frac{\sqrt{d+e x}}{a b+b^2 x} \, dx}{3 b^2 e \sqrt{a^2+2 a b x+b^2 x^2}}\\ &=\frac{2 (A b-a B) (a+b x) \sqrt{d+e x}}{b^2 \sqrt{a^2+2 a b x+b^2 x^2}}+\frac{2 B (a+b x) (d+e x)^{3/2}}{3 b e \sqrt{a^2+2 a b x+b^2 x^2}}+\frac{\left (2 \left (b^2 d-a b e\right ) \left (\frac{3}{2} A b^2 e-\frac{3}{2} a b B e\right ) \left (a b+b^2 x\right )\right ) \int \frac{1}{\left (a b+b^2 x\right ) \sqrt{d+e x}} \, dx}{3 b^4 e \sqrt{a^2+2 a b x+b^2 x^2}}\\ &=\frac{2 (A b-a B) (a+b x) \sqrt{d+e x}}{b^2 \sqrt{a^2+2 a b x+b^2 x^2}}+\frac{2 B (a+b x) (d+e x)^{3/2}}{3 b e \sqrt{a^2+2 a b x+b^2 x^2}}+\frac{\left (4 \left (b^2 d-a b e\right ) \left (\frac{3}{2} A b^2 e-\frac{3}{2} a b B e\right ) \left (a b+b^2 x\right )\right ) \operatorname{Subst}\left (\int \frac{1}{a b-\frac{b^2 d}{e}+\frac{b^2 x^2}{e}} \, dx,x,\sqrt{d+e x}\right )}{3 b^4 e^2 \sqrt{a^2+2 a b x+b^2 x^2}}\\ &=\frac{2 (A b-a B) (a+b x) \sqrt{d+e x}}{b^2 \sqrt{a^2+2 a b x+b^2 x^2}}+\frac{2 B (a+b x) (d+e x)^{3/2}}{3 b e \sqrt{a^2+2 a b x+b^2 x^2}}-\frac{2 (A b-a B) \sqrt{b d-a e} (a+b x) \tanh ^{-1}\left (\frac{\sqrt{b} \sqrt{d+e x}}{\sqrt{b d-a e}}\right )}{b^{5/2} \sqrt{a^2+2 a b x+b^2 x^2}}\\ \end{align*}
Mathematica [A] time = 0.0964527, size = 114, normalized size = 0.66 \[ \frac{2 (a+b x) \left (\sqrt{b} \sqrt{d+e x} (-3 a B e+3 A b e+b B (d+e x))+3 e (a B-A b) \sqrt{b d-a e} \tanh ^{-1}\left (\frac{\sqrt{b} \sqrt{d+e x}}{\sqrt{b d-a e}}\right )\right )}{3 b^{5/2} e \sqrt{(a+b x)^2}} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.01, size = 226, normalized size = 1.3 \begin{align*}{\frac{2\,bx+2\,a}{3\,{b}^{2}e} \left ( -3\,A\arctan \left ({\frac{\sqrt{ex+d}b}{\sqrt{ \left ( ae-bd \right ) b}}} \right ) ab{e}^{2}+3\,A\arctan \left ({\frac{\sqrt{ex+d}b}{\sqrt{ \left ( ae-bd \right ) b}}} \right ){b}^{2}de+B\sqrt{ \left ( ae-bd \right ) b} \left ( ex+d \right ) ^{{\frac{3}{2}}}b+3\,B\arctan \left ({\frac{\sqrt{ex+d}b}{\sqrt{ \left ( ae-bd \right ) b}}} \right ){a}^{2}{e}^{2}-3\,B\arctan \left ({\frac{\sqrt{ex+d}b}{\sqrt{ \left ( ae-bd \right ) b}}} \right ) abde+3\,A\sqrt{ \left ( ae-bd \right ) b}\sqrt{ex+d}be-3\,B\sqrt{ \left ( ae-bd \right ) b}\sqrt{ex+d}ae \right ){\frac{1}{\sqrt{ \left ( bx+a \right ) ^{2}}}}{\frac{1}{\sqrt{ \left ( ae-bd \right ) b}}}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{{\left (B x + A\right )} \sqrt{e x + d}}{\sqrt{{\left (b x + a\right )}^{2}}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 1.32422, size = 471, normalized size = 2.72 \begin{align*} \left [-\frac{3 \,{\left (B a - A b\right )} e \sqrt{\frac{b d - a e}{b}} \log \left (\frac{b e x + 2 \, b d - a e - 2 \, \sqrt{e x + d} b \sqrt{\frac{b d - a e}{b}}}{b x + a}\right ) - 2 \,{\left (B b e x + B b d - 3 \,{\left (B a - A b\right )} e\right )} \sqrt{e x + d}}{3 \, b^{2} e}, \frac{2 \,{\left (3 \,{\left (B a - A b\right )} e \sqrt{-\frac{b d - a e}{b}} \arctan \left (-\frac{\sqrt{e x + d} b \sqrt{-\frac{b d - a e}{b}}}{b d - a e}\right ) +{\left (B b e x + B b d - 3 \,{\left (B a - A b\right )} e\right )} \sqrt{e x + d}\right )}}{3 \, b^{2} e}\right ] \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\left (A + B x\right ) \sqrt{d + e x}}{\sqrt{\left (a + b x\right )^{2}}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 1.134, size = 227, normalized size = 1.31 \begin{align*} -\frac{2 \,{\left (B a b d \mathrm{sgn}\left (b x + a\right ) - A b^{2} d \mathrm{sgn}\left (b x + a\right ) - B a^{2} e \mathrm{sgn}\left (b x + a\right ) + A a b e \mathrm{sgn}\left (b x + a\right )\right )} \arctan \left (\frac{\sqrt{x e + d} b}{\sqrt{-b^{2} d + a b e}}\right )}{\sqrt{-b^{2} d + a b e} b^{2}} + \frac{2 \,{\left ({\left (x e + d\right )}^{\frac{3}{2}} B b^{2} e^{2} \mathrm{sgn}\left (b x + a\right ) - 3 \, \sqrt{x e + d} B a b e^{3} \mathrm{sgn}\left (b x + a\right ) + 3 \, \sqrt{x e + d} A b^{2} e^{3} \mathrm{sgn}\left (b x + a\right )\right )} e^{\left (-3\right )}}{3 \, b^{3}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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